338. Counting Bits
Easy80.4% acceptance1,575,324 / 1,958,917 submissions
Asked by 9 companies
Topics
Given an integer n, return an array ans of length n + 1 such that for each i (0 <= i <= n), ans[i] is the number of 1's in the binary representation of i.
Example 1:
Input: n = 2 Output: [0,1,1] Explanation: 0 --> 0 1 --> 1 2 --> 10
Example 2:
Input: n = 5 Output: [0,1,1,2,1,2] Explanation: 0 --> 0 1 --> 1 2 --> 10 3 --> 11 4 --> 100 5 --> 101
Constraints:
0 <= n <= 105
Follow up:
- It is very easy to come up with a solution with a runtime of
O(n log n). Can you do it in linear timeO(n)and possibly in a single pass? - Can you do it without using any built-in function (i.e., like
__builtin_popcountin C++)?
Hints
Hint 1
You should make use of what you have produced already.
Hint 2
Divide the numbers in ranges like [2-3], [4-7], [8-15] and so on. And try to generate new range from previous.
Hint 3
Or does the odd/even status of the number help you in calculating the number of 1s?